Can I apply and/or to a list? If not, what can I do to get similar result?

andmap, ormap

or for/or, for/and

or turn your list into syntax, insert and/or, and evaluate :stuck_out_tongue: (don’t do that)

Note that andmap and for/and behave differently regarding list lengths if you apply them to more than one list

transducers version, for my own amusement: (transduce sequence #:into (into-all-match? predicate)) (like (andmap predicate sequence) but works with any sequence)

if your list is a list of boolean values (or are interpreted as such), then (andmap values my-list) does the job. You can use identity instead of values.

Otherwise (untested): (define (and-proc . vals) (or (empty? vals) (and (first vals) (and-proc (rest vals)))))