spdegabrielle
2020-6-19 09:31:59
sorawee
2020-6-19 15:37:58
I was under the impression that you are the kid in your profile picture…
aaroncooperlob
2020-6-19 16:40:31
@aaroncooperlob has joined the channel
anything
2020-6-19 19:34:38
@plragde I’m trying to derive O(e^{n / lg n}) but I’m not being able to. When I first looked, I thought it would be a matter of taking the log of the expression and raising it to the base (of the log). When I do that, I get n lg(2 * 2^{1/lg n}) and not the beautiful e^{n / lg n}. Can you point me in the direction to see this equivalence? Thank you!
edamiani
2020-6-19 20:37:17
@edamiani has joined the channel
enyala9733
2020-6-20 03:29:09
@enyala9733 has joined the channel
enyala9733
2020-6-20 03:36:11
can I use it as a Profile photo